In the disproportionation reaction 3 HClO3 arrow HClO4 + Cl2 + 2 O2 + H2O the equivalent mass of the oxidising agent is (molar mass of HClO3 = 84.45)

Question

In the disproportionation reaction 3 HClO3 arrow HClO4 + Cl2 + 2 O2 + H2O the equivalent mass of the oxidising agent is (molar mass of HClO3 = 84.45) (A) 16.89 (B) 32.22 (C) 84.45 (D) 28.15

Tardigrade Admin · Accepted Answer

ClO-3 arrow Cl20; In ClO-3 = x - 6 = - 1 or x = + 5 Eq. mass of ClO-3 = ( textMol. mass of ClO-3/ textOxidation number change) = (84.45/5) = 16.89

Q. In the disproportionation reaction $3 H Cl O_{3} \to H Cl O_{4} + C l_{2} + 2 O_{2} + H_{2} O$ the equivalent mass of the oxidising agent is (molar mass of $H Cl O_{3} = 84.45$ )

16.89

32.22

84.45

28.15

$Cl O_{3}^{-} \to C l_{2}^{0}$ ;
In $Cl O_{3}^{-} = x - 6 = - 1$ or $x = + 5$
Eq. mass of $Cl O_{3}^{-}$
$= \frac{Mol. mass of Cl O _{3}^{-}}{Oxidation number change} = \frac{84.45}{5} = 16.89$

Q. In the disproportionation reaction 3HClO3​→HClO4​+Cl2​+2O2​+H2​O the equivalent mass of the oxidising agent is (molar mass of HClO3​=84.45)