In the decay sequence, 23892U-[-x1] 23490Th-[-x2] 23491Pa -[-x3]234Z-[-x4] 23090Th x1,x2, x3 and x4 are particles/radiation emitted by the respective isotopes. The correct option(s) is(are)

Question

In the decay sequence, 23892U->[-x1] 23490Th->[-x2] 23491Pa ->[-x3]234Z->[-x4] 23090Th x1,x2, x3 and x4 are particles/radiation emitted by the respective isotopes. The correct option(s) is(are) (A) x1 will deflect towards negatively charged plate (B) x2 is β- (C) x3 is&gamma;-ray (D) Z is an isotope of uranium

Tardigrade Admin · Accepted Answer

92U238 → 90Th234 + 2He4 90Th234 → 91Pa234 + -1e0 91Pa234 → 92Z234 + -1e0 92Z234 → 90Th230 + 2He4 ∴ x1 = α ; x2 = x3 = -1β0 ; x4 = α Z has atomic number 92.

$x_{1}$ will deflect towards negatively charged plate

$x_{2}$ is $β^{-}$

$x_{3}$ is $γ$ -ray

$Z$ is an isotope of uranium

$_{92} U^{238} \to_{90} T h^{234} +_{2} H e^{4}$
$_{90} T h^{234} \to_{91} P a^{234} + - 1^{e^{0}}$
$_{91} P a^{234} \to_{92} Z^{234} + - 1^{e^{0}}$
$_{92} Z^{234} \to_{90} T h^{230} +_{2} H e^{4}$
$∴ x_{1} = α; x_{2} = x_{3} =_{- 1} β^{0}; x_{4} = α$
Z has atomic number 92.

Q. In the decay sequence, X92238​X2922238​U−xX1​​X90234​X2902234​Th−xX2​​X91234​X2912234​Pa−xX3​​X234​X22234​ZX−×4​​X90230​X2902230​Th x1​,x2​,x3​ and x4​ are particles/radiation emitted by the respective isotopes. The correct option(s) is(are)

x1​ will deflect towards negatively charged plate

x2​ is β−

x3​ isγ-ray

Z is an isotope of uranium

92​U238→90​Th234+2​He4 90​Th234→91​Pa234+−1e0 91​Pa234→92​Z234+−1e0 92​Z234→90​Th230+2​He4 ∴x1​=α;x2​=x3​=−1​β0;x4​=α Z has atomic number 92.

$x_{1}$ will deflect towards negatively charged plate

$x_{2}$ is $β^{-}$

$x_{3}$ is $γ$ -ray

$Z$ is an isotope of uranium

$_{92} U^{238} \to_{90} T h^{234} +_{2} H e^{4}$
$_{90} T h^{234} \to_{91} P a^{234} + - 1^{e^{0}}$
$_{91} P a^{234} \to_{92} Z^{234} + - 1^{e^{0}}$
$_{92} Z^{234} \to_{90} T h^{230} +_{2} H e^{4}$
$∴ x_{1} = α; x_{2} = x_{3} =_{- 1} β^{0}; x_{4} = α$
Z has atomic number 92.