In the cyclic process shown in P-V diagram, the magnitude of the work done is

Question

In the cyclic process shown in P-V diagram, the magnitude of the work done is <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/c-urafyauk0obv.png" /> (A) π ((P2 - P1/2))2 (B) π ((V2 - V1/2))2 (C) (π /4)(.P2-P1.)(.V2-V1.) (D) π( V 2- V 1)2

Tardigrade Admin · Accepted Answer

Work done = Area bounded by the circle =π ((. P2 - P1 .)/2)((. V2 - V1 .)/2) =(π /4)(.P2-P1.)(.V2-V1.)

Q. In the cyclic process shown in P-V diagram, the magnitude of the work done is

$π (\frac{P _{2} - P _{1}}{2})^{2}$

$π (\frac{V _{2} - V _{1}}{2})^{2}$

$\frac{π}{4} (P_{2} - P_{1}) (V_{2} - V_{1})$

$π (V_{2} - V_{1})^{2}$

Work done = Area bounded by the circle

$= π \frac{( P _{2} - P _{1} )}{2} \frac{( V _{2} - V _{1} )}{2}$

$= \frac{π}{4} (P_{2} - P_{1}) (V_{2} - V_{1})$

Q. In the cyclic process shown in P-V diagram, the magnitude of the work done is

π(2P2​−P1​​)2

π(2V2​−V1​​)2

4π​(P2​−P1​)(V2​−V1​)

π(V2​−V1​)2

Work done = Area bounded by the circle =π2(P2​−P1​)​2(V2​−V1​)​ =4π​(P2​−P1​)(V2​−V1​)

$π (\frac{P _{2} - P _{1}}{2})^{2}$

$π (\frac{V _{2} - V _{1}}{2})^{2}$

$\frac{π}{4} (P_{2} - P_{1}) (V_{2} - V_{1})$

$π (V_{2} - V_{1})^{2}$

Work done = Area bounded by the circle

$= π \frac{( P _{2} - P _{1} )}{2} \frac{( V _{2} - V _{1} )}{2}$

$= \frac{π}{4} (P_{2} - P_{1}) (V_{2} - V_{1})$