Question

In the coordination compound $K_4[Ni(CN{)}_4]$, the oxidation state of nickel is

• A. -1
• B. 0
• C. +1
• D. + 2

Answer 1

Answer: (B)

$K_4[Ni(CN{)}_4]$ O.N. of Ni = 4 $\times$ 1 - 4 $\times$ 1 = 0.