In the conversion of Br2 to BrO3-, the oxidation number of Br changes from

Question

In the conversion of Br2 to BrO3-, the oxidation number of Br changes from (A) zero to +5  (B)  +1 to +5  (C) zero to -3  (D)  +2 to +5

Tardigrade Admin · Accepted Answer

Bromine has zero oxidation state because it is in free state overset0 mathopB r2 xrightarrow[]BrO3- oversetx mathopB O3- underline2 x+(-2× 3)=-1 x+(-6)=-1 x=+6-1 =+5 So, oxidation number changes from 0 to +5 .

Q. In the conversion of $B r_{2}$ to $B r O_{3}^{-},$ the oxidation number of Br changes from

zero to $+ 5$

$+ 1$ to $+ 5$

zero to $- 3$

$+ 2$ to $+ 5$

Bromine has zero oxidation state because it is in free state $B 0 r_{2} B r O_{3}^{-}$ $B x O_{3}^{- \underline{2}}$ $x + (- 2 \times 3) = - 1$ $x + (- 6) = - 1$ $x = + 6 - 1$ $= + 5$ So, oxidation number changes from 0 to $+ 5$ .

Q. In the conversion of Br2​ to BrO3−​, the oxidation number of Br changes from

zero to +5

+1 to +5

zero to −3

+2 to +5