In the compound CH 2= CH - CH 2- CH 2- C ≡ CH, the ( C 2- C 3) bond is of the type:

Question

In the compound CH 2= CH - CH 2- CH 2- C ≡ CH, the ( C 2- C 3) bond is of the type: (A) s p-s p2 (B) s p3-s p3 (C) s p-s p3 (D) s p2-s p3

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/3f1e389009a7b74cfc8efab83fc75b1c-.png" /> Hence, C 2 and C 3 are s p2-and s p3-hybridised

Q. In the compound $C H_{2} = C H - C H_{2} - C H_{2} - C \equiv C H$ , the $(C_{2} - C_{3})$ bond is of the type:

$s p - s p^{2}$

$s p^{3} - s p^{3}$

$s p - s p^{3}$

$s p^{2} - s p^{3}$

Hence, $C_{2}$ and $C_{3}$ are $s p^{2}$ -and $s p^{3}$ -hybridised

Q. In the compound CH2​=CH−CH2​−CH2​−C≡CH, the (C2​−C3​) bond is of the type:

sp−sp2

sp3−sp3

sp−sp3

sp2−sp3