Q.
In the circuit, the galvanometer G shows zero deflection. If the batteries A and B have negligible internal resistance, the value of the resistor R will be
The galvanometer shows zero deflection ie, current through XY is zero.
As a result potential drop across R is 2V, circuit can be redrawn as I=500+R12
Voltage across R, V=IR ⇒2=500+R12×R ⇒1000+2R=12R ⇒R=100Ω