In the circuit shown the cells A and B have negligible resistances. For VA = 12V, R1 = 500 Ω and R = 100 Ω the galvanometer (G) shows no deflection. The value of VB is :

Question

In the circuit shown the cells A and B have negligible resistances. For VA = 12V, R1 = 500 Ω and R = 100 Ω the galvanometer (G) shows no deflection. The value of VB is : (A) 4 V (B) 2 V (C) 12 V (D) 6 V

Tardigrade Admin · Accepted Answer

Since deflection in galvanometer is zero so current will flow as shown in the above diagram. current, I = (VA/R1+R) = (12/500+100) = (12/600) So VB IR-(12/600)×100 = 2V

Q. In the circuit shown the cells $A$ and $B$ have negligible resistances. For $V_{A} = 12 V, R_{1} = 500 Ω$ and $R = 100 Ω$ the galvanometer $(G)$ shows no deflection. The value of $V_{B}$ is :

4 V

2 V

12 V

6 V

Since deflection in galvanometer is zero so current will flow as shown in the above diagram.
current, $I = \frac{V _{A}}{R _{1} + R} = \frac{12}{500 + 100} = \frac{12}{600}$
So $V_{B} I R - \frac{12}{600} \times 100 = 2 V$

Q. In the circuit shown the cells A and B have negligible resistances. For VA​=12V,R1​=500Ω and R=100Ω the galvanometer (G) shows no deflection. The value of VB​ is :

4 V

2 V

12 V

6 V

Since deflection in galvanometer is zero so current will flow as shown in the above diagram. current, I=R1​+RVA​​=500+10012​=60012​ So VB​IR−60012​×100=2V

Q. In the circuit shown the cells $A$ and $B$ have negligible resistances. For $V_{A} = 12 V, R_{1} = 500 Ω$ and $R = 100 Ω$ the galvanometer $(G)$ shows no deflection. The value of $V_{B}$ is :

Since deflection in galvanometer is zero so current will flow as shown in the above diagram.
current, $I = \frac{V _{A}}{R _{1} + R} = \frac{12}{500 + 100} = \frac{12}{600}$
So $V_{B} I R - \frac{12}{600} \times 100 = 2 V$