In the circuit shown in the given figure, the resistances R1 and R2 are respectively

Question

In the circuit shown in the given figure, the resistances R1 and R2 are respectively (A) 14 Ω and 40 Ω (B) 40 Ω and 14 Ω (C) 40 Ω and 30 Ω (D) 14 Ω and 30 Ω

Tardigrade Admin · Accepted Answer

Potential difference across 20 Ω = 20 × 1 = 20 V = potential difference across R2 Current in R2 = 0.5 A ∴ : : R2 = (20 V/0.5 A) = 40 Ω Potential difference across R1 = 69 V - 20 V =49 V Current in R1 = 0.5 A + (20/10) A + A = 3.5 A ∴ : :: R1 = (49/3.5) = 14 Ω

Q. In the circuit shown in the given figure, the resistances $R_{1}$ and $R_{2}$ are respectively

$14 Ω$ and $40 Ω$

$40 Ω$ and $14 Ω$

$40 Ω$ and $30 Ω$

$14 Ω$ and $30 Ω$

Q. In the circuit shown in the given figure, the resistances R1​ and R2​ are respectively

14Ω and 40Ω

40Ω and 14Ω

40Ω and 30Ω

14Ω and 30Ω

Potential difference across 20Ω=20×1 =20 V = potential difference across R2​ Current in R2​=0.5A ∴R2​=0.5A20V​=40Ω Potential difference across R1​=69 V−20 V =49 V Current in R1​=0.5A+1020​ A+ A=3.5 A ∴R1​=3.549​=14Ω

Q. In the circuit shown in the given figure, the resistances $R_{1}$ and $R_{2}$ are respectively

$14 Ω$ and $40 Ω$

$40 Ω$ and $14 Ω$

$40 Ω$ and $30 Ω$

$14 Ω$ and $30 Ω$