In the circuit shown in the following figure, the value of Y is

Question

In the circuit shown in the following figure, the value of Y is <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-pfuqrlwtunru.png" /> (A) 0 (B) 1 (C) fluctuates between 0 and 1 (D) indeterminate as the circuit cannot be realized

Tardigrade Admin · Accepted Answer

Lower NOT gate inverts input to zero. NOT gate from NAND gate inverts this output to

1

and upper NAND gate converts this input

1

and input

0

to

1

.
Thus

A = 1

and

B = 1

become inputs of NAND gate giving final output as zero. Choice A is correct.

Q. In the circuit shown in the following figure, the value of $Y$ is

$0$

$1$

fluctuates between $0$ and $1$

indeterminate as the circuit cannot be realized

Lower NOT gate inverts input to zero. NOT gate from NAND gate inverts this output to $1$ and upper NAND gate converts this input $1$ and input $0$ to $1$ .
Thus $A = 1$ and $B = 1$ become inputs of NAND gate giving final output as zero. Choice A is correct.

Q. In the circuit shown in the following figure, the value of Y is

0

1

fluctuates between 0 and 1

indeterminate as the circuit cannot be realized

Lower NOT gate inverts input to zero. NOT gate from NAND gate inverts this output to 1 and upper NAND gate converts this input 1 and input 0 to 1 . Thus A=1 and B=1 become inputs of NAND gate giving final output as zero. Choice A is correct.

Q. In the circuit shown in the following figure, the value of $Y$ is

$0$

$1$

fluctuates between $0$ and $1$

Lower NOT gate inverts input to zero. NOT gate from NAND gate inverts this output to $1$ and upper NAND gate converts this input $1$ and input $0$ to $1$ .
Thus $A = 1$ and $B = 1$ become inputs of NAND gate giving final output as zero. Choice A is correct.