In the circuit shown in the figure, the total charge in 750 μ C and the voltage across capacitor C 2 is 20 V. Then the charge on capacitor C 2 is :

Question

In the circuit shown in the figure, the total charge in 750 μ C and the voltage across capacitor C 2 is 20 V. Then the charge on capacitor C 2 is : (A) 590 μ C (B) 450 μ C (C) 650 μ C (D) 160 μ C

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/0954e36183a770b172cc7a0703ad69d2-.png" /> q 3=20 × 8=160 μ C ∴ q 2=750-160=590 μ C

Q. In the circuit shown in the figure, the total charge in $750 μ C$ and the voltage across capacitor $C_{2}$ is $20 V$ . Then the charge on capacitor $C_{2}$ is :

$590 μ C$

$450 μ C$

$650 μ C$

$160 μ C$

$q_{3} = 20 \times 8 = 160 μ C$
$∴ q_{2} = 750 - 160 = 590 μ C$

Q. In the circuit shown in the figure, the total charge in 750μC and the voltage across capacitor C2​ is 20V. Then the charge on capacitor C2​ is :

590μC

450μC

650μC

160μC