In the circuit shown in the figure, reading of voltmeter is V1 when only S1 is closed, reading of voltmeter is V2 when only S2 is closed and reading of voltmeter is V3 when both S1 and S2 are closed. Then

Question

In the circuit shown in the figure, reading of voltmeter is V1 when only S1 is closed, reading of voltmeter is V2 when only S2 is closed and reading of voltmeter is V3 when both S1 and S2 are closed. Then <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-wwdeil9z3bh3yz1n.jpg" /> (A) V3>V2>V1 (B) V2>V1>V3 (C) V3>V1>V2 (D) V1>V2>V3

Tardigrade Admin · Accepted Answer

V2>V1>V3 When S1 closed Solution

V1=(3 R/R + 3 R)E=(3/4)E When S2 is closed Solution

V2=(6 R/R + 6 R)E=(6/7)E When both S1 and S2 are closed Solution

V3=(2 R/R + 2 R)E=(2 E/3) ∴ V2>V1>V3

Q. In the circuit shown in the figure, reading of voltmeter is $V_{1}$ when only $S_{1}$ is closed, reading of voltmeter is $V_{2}$ when only $S_{2}$ is closed and reading of voltmeter is $V_{3}$ when both $S_{1}$ and $S_{2}$ are closed. Then

$V_{3} > V_{2} > V_{1}$

$V_{2} > V_{1} > V_{3}$

$V_{3} > V_{1} > V_{2}$

$V_{1} > V_{2} > V_{3}$

$V_{2} > V_{1} > V_{3}$
When $S_{1}$ closed

$V_{1} = \frac{3 R}{R + 3 R} E = \frac{3}{4} E$
When $S_{2}$ is closed

$V_{2} = \frac{6 R}{R + 6 R} E = \frac{6}{7} E$
When both $S_{1}$ and $S_{2}$ are closed

$V_{3} = \frac{2 R}{R + 2 R} E = \frac{2 E}{3}$
$∴ V_{2} > V_{1} > V_{3}$

Q. In the circuit shown in the figure, reading of voltmeter is V1​ when only S1​ is closed, reading of voltmeter is V2​ when only S2​ is closed and reading of voltmeter is V3​ when both S1​ and S2​ are closed. Then

V3​>V2​>V1​

V2​>V1​>V3​

V3​>V1​>V2​

V1​>V2​>V3​