Question

In the circuit shown in the figure, if the potential at point $A$ is taken to be zero, the potential at point $B$ is

• A. +1 V
• B. -1 V
• C. +2 V
• D. -2 V

Answer 1

Answer: (A)

Along the path $ACDB$
$V_B=V_A+1V+2\times 1V-2V$
$=0+1+2-2=1V$