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Tardigrade
Question
Physics
In the circuit shown in figure, X C =100 Ω, X L =200 Ω and R=100 Ω. The effective current through the source is
Q. In the circuit shown in figure,
X
C
=
100
Ω
,
X
L
=
200
Ω
and
R
=
100
Ω
. The effective current through the source is
67
154
Alternating Current
Report Error
A
2
A
B
2
2
A
C
0.5
A
D
0.4
A
Solution:
I
R
=
R
V
=
100
200
=
2
A
I
′
=
X
L
−
X
C
V
=
100
200
=
2
A
I
=
I
R
2
+
I
′2
=
2
2
A