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  4. In the circuit shown in figure, X C =100 Ω, X L =200 Ω and R=100 Ω. The effective current through the source is

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Q. In the circuit shown in figure, $X_{ C }=100\, \Omega, X_{ L }=200 \,\Omega$ and $R=100\, \Omega$. The effective current through the source isPhysics Question Image

Alternating Current

Solution:

$ I_{ R }=\frac{V}{R} =\frac{200}{100}=2 A $
$I^{\prime} =\frac{V}{X_{ L }-X_{ C }}=\frac{200}{100}=2\, A $
$I=\sqrt{I_{ R }^{2}+I^{\prime 2}}=2 \sqrt{2} A$
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