In the circuit shown in figure, time constant and steady state current will be

Question

In the circuit shown in figure, time constant and steady state current will be <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-qwdnch2aglwkemsm.jpg" /> (A) 0.25 s, 0.75 A (B) 0.75s,0.25A (C) 0.25 s, 0.25 A (D) 0.5 s, 0.5 A

Tardigrade Admin · Accepted Answer

Equivalent resistance is 8 Ω Therefore time constant is, τ=(L/Re q) τ=(2/8)=0.25 s And the steady-state current is, i0=(ϵ /R) i0=(6/8)=0.75 A

Q. In the circuit shown in figure, time constant and steady state current will be

$0.25 s, 0.75 A$

$0.75 s, 0.25 A$

$0.25 s, 0.25 A$

$0.5 s, 0.5 A$

Equivalent resistance is $8 Ω$
Therefore time constant is,
$τ = \frac{L}{R _{e q}}$
$τ = \frac{2}{8} = 0.25 s$
And the steady-state current is,
$i_{0} = \frac{ϵ}{R}$
$i_{0} = \frac{6}{8} = 0.75 A$

Q. In the circuit shown in figure, time constant and steady state current will be

0.25s,0.75A

0.75s,0.25A

0.25s,0.25A

0.5s,0.5A

Equivalent resistance is 8Ω Therefore time constant is, τ=Req​L​ τ=82​=0.25s And the steady-state current is, i0​=Rϵ​ i0​=86​=0.75A

$0.25 s, 0.75 A$

$0.75 s, 0.25 A$

$0.25 s, 0.25 A$

$0.5 s, 0.5 A$

Equivalent resistance is $8 Ω$
Therefore time constant is,
$τ = \frac{L}{R _{e q}}$
$τ = \frac{2}{8} = 0.25 s$
And the steady-state current is,
$i_{0} = \frac{ϵ}{R}$
$i_{0} = \frac{6}{8} = 0.75 A$