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Q. In the circuit shown in figure, time constant and steady state current will be
Question

NTA AbhyasNTA Abhyas 2022

Solution:

Equivalent resistance is $8 \, \Omega$
Therefore time constant is,
$\tau=\frac{L}{R_{e q}}$
$\tau=\frac{2}{8}=0.25 \, s$
And the steady-state current is,
$i_{0}=\frac{\epsilon }{R}$
$i_{0}=\frac{6}{8}=0.75 \, A$