In the circuit shown in figure, the potential difference between the points A and B will be

Question

In the circuit shown in figure, the potential difference between the points A and B will be (A) (2/3) V (B) (8/0) V 3 (C) (4/3) V (D) 2V

Tardigrade Admin · Accepted Answer

The circuit diagram may be redrawn as shown here.

Obviosuly,

I_{C A D} = I_{CB D} = \frac{2}{15} A

∴ V_{C} - V_{A} = \frac{2}{15} A \times 5 Ω = \frac{2}{3} V

and

V_{C} - V_{B} = \frac{2}{15} A \times 10 Ω = \frac{4}{3} V

∴ V_{A} - V_{B} = (V_{C} - V_{B}) - (V_{C} - V_{A})

= \frac{4}{3} V - \frac{2}{3} V = \frac{2}{3} V

Q. In the circuit shown in figure, the potential difference between the points $A$ and $B$ will be