In the circuit shown in figure the heat produced in the 5Ω resistor due to the current flowing through it is 10 cal/s. The heat generated in the 4Ω resistor is

Question

In the circuit shown in figure the heat produced in the 5Ω resistor due to the current flowing through it is 10 cal/s. The heat generated in the 4Ω resistor is (A) 1 cal/s (B) 2 cal/s (C) 3 cal/s (D) 4 cal/s

Tardigrade Admin · Accepted Answer

Since, resistance in upper branch of the circuit is twice the
resistance in lower branch. Hence, current there will be half

P_{4} = (i /2)^{2} (4) (p = i^{2} R)

P_{5} = (i)^{2} (5)

or

\frac{P _{4}}{P _{5}} = \frac{1}{5}

P_{4} = \frac{P _{5}}{5} = \frac{10}{5} = 2 c a l / s

∴

Correct option is (b)

Q. In the circuit shown in figure the heat produced in the 5Ω resistor due to the current flowing through it is 10 cal/s. The heat generated in the 4Ω resistor is

1 cal/s

2 cal/s

3 cal/s

4 cal/s

Since, resistance in upper branch of the circuit is twice the resistance in lower branch. Hence, current there will be half P4​=(i/2)2(4)(p=i2R) P5​=(i)2(5) or P5​P4​​=51​ P4​=5P5​​=510​=2cal/s ∴Correct option is (b)

Q. In the circuit shown in figure the heat produced in the $5Ω$ resistor due to the current flowing through it is 10 cal/s.
The heat generated in the $4Ω$ resistor is