Question

In the circuit shown in figure, the charge on the $5\mu F$ capacitor will be

• A. $4.5\mu C$
• B. $9\mu C$
• C. $15\mu C$
• D. none of these

Answer 1

Answer: (C)

Potential difference across upper branch is $6V$.

$V_2=V\left(\frac{C_1}{C_1+C_2}\right)=10\left[\frac{3}{3+7}\right]=3V$
Hence, potential difference across $5\mu F$ capacitor is $3V$.
Thus, charge in $5\mu F$ capacitor is
$Q_{5\mu F}=5\times 3=15\mu C$