In the circuit shown in figure, the base current IB is 10 μA and the collector current is 5.2 mA . The voltage ( VBE ) across the base and emitter is

Question

In the circuit shown in figure, the base current IB is 10 μA and the collector current is 5.2 mA . The voltage ( VBE ) across the base and emitter is <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-ziibbopnbtov.png" /> (A) 0.1V (B) 0.5 V (C) 0.25V (D) 0.7V

Tardigrade Admin · Accepted Answer

V BE = V CC - I B R B V BE =5.5-(10 × 10-6) ×(5 × 105)=0.5 V

Q. In the circuit shown in figure, the base current $I_{B}$ is $10 μ A$ and the collector current is $5.2 m A$ . The voltage ( $V_{BE}$ ) across the base and emitter is

$0.1 V$

$0.5 V$

$0.25 V$

$0.7 V$

$V_{BE} = V_{CC} - I_{B} R_{B}$
$V_{BE} = 5.5 - (10 \times 1 0^{- 6}) \times (5 \times 1 0^{5}) = 0.5 V$

Q. In the circuit shown in figure, the base current IB​ is 10μA and the collector current is 5.2mA . The voltage ( VBE​ ) across the base and emitter is

0.1V

0.5V

0.25V

0.7V