In the circuit shown assume the diode to be ideal. When Vi increases from 2 V to 6 V, the change in the current is (in mA)

Question

In the circuit shown assume the diode to be ideal. When Vi increases from 2 V to 6 V, the change in the current is (in mA) (A) zero (B) 20 (C) (80/3) (D) 40

Tardigrade Admin · Accepted Answer

I text initlal =0 <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/b158726a3f52a861729d57d9eb5c8c5a-.png" /> I text final =(3/150)=0.02 A So, change in I=0.02 A =20 mA

Q. In the circuit shown assume the diode to be ideal. When $V_{i}$ increases from $2 V$ to $6 V$ , the change in the current is (in $m A$ )

zero

$20$

$\frac{80}{3}$

$40$

$I_{initlal} = 0$

$I_{final} = \frac{3}{150} = 0.02 A$
So, change in $I = 0.02 A = 20 m A$

Q. In the circuit shown assume the diode to be ideal. When Vi​ increases from 2V to 6V, the change in the current is (in mA)