In the circuit diagram shown, XC=100 Ω, XL=200 Ω and R=100 Ω. The effective current through the source is m √n ampere. Find (m+n).

Question

In the circuit diagram shown, XC=100 Ω, XL=200 Ω and R=100 Ω. The effective current through the source is m √n ampere. Find (m+n). (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/ef6fd11b6143f9d0759d34b623cdf6af-.png" /> IR=(V/R)=(200/100)=2 A I'=(V/XL-XC)=(200/100)=2 A I=√IR2+I prime 2=2 √2 A

Q. In the circuit diagram shown, $X_{C} = 100 Ω, X_{L} = 200 Ω$ and $R = 100 Ω$ . The effective current through the source is $m n$ ampere. Find $(m + n)$ .

$I_{R} = \frac{V}{R} = \frac{200}{100} = 2 A$
$I^{'} = \frac{V}{X _{L} - X _{C}} = \frac{200}{100} = 2 A$
$I = I_{R}^{2} + I^{'2} = 22 A$

Q. In the circuit diagram shown, XC​=100Ω,XL​=200Ω and R=100Ω. The effective current through the source is mn​ ampere. Find (m+n).

IR​=RV​=100200​=2A I′=XL​−XC​V​=100200​=2A I=IR2​+I′2​=22​A

Q. In the circuit diagram shown, $X_{C} = 100 Ω, X_{L} = 200 Ω$ and $R = 100 Ω$ . The effective current through the source is $m n$ ampere. Find $(m + n)$ .

$I_{R} = \frac{V}{R} = \frac{200}{100} = 2 A$
$I^{'} = \frac{V}{X _{L} - X _{C}} = \frac{200}{100} = 2 A$
$I = I_{R}^{2} + I^{'2} = 22 A$