In the circuit diagram shown in the figure below, the resultant capacitance between P and Q is

Question

In the circuit diagram shown in the figure below, the resultant capacitance between P and Q is (A) 47 μ F (B) 3 μ F (C) 60 μ F (D) 10 μ F

Tardigrade Admin · Accepted Answer

The given circuit can be drawn as: <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/b0d2e337f465ff46b12bf173798e6623-.png" /> C=(3+2) μ F =5 μ F (1/CP Q)=(1/5)+(1/20)+(1/12) =(20/60)=(1/3) ⇒ CP Q=3 μ F

Q. In the circuit diagram shown in the figure below, the resultant capacitance between $P$ and $Q$ is

$47 μ F$

$3 μ F$

$60 μ F$

$10 μ F$

The given circuit can be drawn as:

$C = (3 + 2) μ F = 5 μ F$
$\frac{1}{C _{PQ}} = \frac{1}{5} + \frac{1}{20} + \frac{1}{12}$
$= \frac{20}{60} = \frac{1}{3}$
$\Rightarrow C_{PQ} = 3 μ F$

Q. In the circuit diagram shown in the figure below, the resultant capacitance between P and Q is

47μF

3μF

60μF

10μF