In the CB mode of a transistor, when the collector voltage is changed by 0.5 volt, the collector current changes by 0.05 mA. The output resistance will be :

Question

In the CB mode of a transistor, when the collector voltage is changed by 0.5 volt, the collector current changes by 0.05 mA. The output resistance will be : (A) 10 k Ω (B) 20 k Ω (C) 5 k Ω (D) 2.5 k Ω

Tardigrade Admin · Accepted Answer

Here: Δ V c =0.5 volt, Δ Ic=0.05 mA =0.05 × 10-3 A Output resistance is given by R text out =(Δ Vc/Δ Ic) =(0.5/0.05 × 10-3)=104 Ω=10 K Ω

Q. In the $CB$ mode of a transistor, when the collector voltage is changed by $0.5$ volt, the collector current changes by $0.05 m A$ . The output resistance will be :

$10 k Ω$

$20 k Ω$

$5 k Ω$

$2.5 k Ω$

Here: $Δ V_{c} = 0.5$ volt,
$Δ I_{c} = 0.05 m A = 0.05 \times 1 0^{- 3} A$
Output resistance is given by
$R_{out} = \frac{Δ V _{c}}{Δ I _{c}}$
$= \frac{0.5}{0.05 \times 1 0 ^{- 3}} = 1 0^{4} Ω = 10 K Ω$

Q. In the CB mode of a transistor, when the collector voltage is changed by 0.5 volt, the collector current changes by 0.05mA. The output resistance will be :

10kΩ

20kΩ

5kΩ

2.5kΩ