In the Cannizzaro's reaction given below: 2Ph-CHO xrightarrowKOH Ph-CH2OH + PhCO-2 The slowest step is

Question

In the Cannizzaro's reaction given below: 2Ph-CHO xrightarrowKOH Ph-CH2OH + PhCO-2 The slowest step is (A) the attack of -OH at the carbonyl group (B) the transfer of hydride to the carbonyl group (C) the abstraction of proton from the carboxylic acid (D) the deprotonation of Ph- CH2OH

Tardigrade Admin · Accepted Answer

Correct answer is (b) the transfer of hydride to the carbonyl group

Q. In the Cannizzaro's reaction given below :
$2 P h - C H O K O H P h - C H_{2} O H + P h C O_{2}^{-}$
The slowest step is

the attack of -OH at the carbonyl group

the transfer of hydride to the carbonyl group

the abstraction of proton from the carboxylic acid

the deprotonation of $P h - C H_{2} O H$

Correct answer is (b) the transfer of hydride to the carbonyl group

Q. In the Cannizzaro's reaction given below : 2Ph−CHOKOH​Ph−CH2​OH+PhCO2−​ The slowest step is

the attack of -OH at the carbonyl group

the transfer of hydride to the carbonyl group

the abstraction of proton from the carboxylic acid

the deprotonation of Ph−CH2​OH

Correct answer is (b) the transfer of hydride to the carbonyl group

Q. In the Cannizzaro's reaction given below :
$2 P h - C H O K O H P h - C H_{2} O H + P h C O_{2}^{-}$
The slowest step is

the deprotonation of $P h - C H_{2} O H$