Question

In the Cannizzaro's reaction given below :
$2Ph-CHO\xrightarrow{KOH} Ph-CH_2OH + PhCO^{-}_{2}$
The slowest step is

• A. the attack of -OH at the carbonyl group
• B. the transfer of hydride to the carbonyl group
• C. the abstraction of proton from the carboxylic acid
• D. the deprotonation of $Ph- CH_2OH$

Answer 1

Answer: (B)

Correct answer is (b) the transfer of hydride to the carbonyl group