In the Cannizzaro's reaction given below: 2 Ph - CHO xrightarrow KOH Ph - CH 2 OH + PhCO 2- The slowest step is

Question

In the Cannizzaro's reaction given below: 2 Ph - CHO xrightarrow KOH Ph - CH 2 OH + PhCO 2- The slowest step is (A) The attack of -OH at the carbonyl group (B) The transfer of hydride to the carbonyl group (C) The abstraction of proton from the carboxylic acid (D) The deprotonation of Ph - CH 2 OH

Tardigrade Admin · Accepted Answer

The slowest step in Cannizzaro reaction is transfer of hydride to the carbonyl group. <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/c-eda3qcxqueh6.png" />

Q. In the Cannizzaro's reaction given below :
$2 P h - C H O K O H P h - C H_{2} O H + P h C O_{2}^{-}$
The slowest step is

The attack of $- O H$ at the carbonyl group

The transfer of hydride to the carbonyl group

The abstraction of proton from the carboxylic acid

The deprotonation of $P h - C H_{2} O H$

The slowest step in Cannizzaro reaction is transfer of hydride to the carbonyl group.

Q. In the Cannizzaro's reaction given below : 2Ph−CHOKOH​Ph−CH2​OH+PhCO2−​ The slowest step is

The attack of −OH at the carbonyl group