Q.
In the binomial expansion of (3ba+3ab)21, the term containing same powers of a and b is
2295
188
NTA AbhyasNTA Abhyas 2020Binomial Theorem
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Solution:
tr+1=21Cr(ba)321−rrb3r =21Cra321−r−6rb3r−321−r
Since, power of a and b are the same ⇒321−r−6r=3r−321−r ⇒32(21−r)=3r+6r=2r 84−4r=3r⇒7r=84⇒r=12
Hence, the 13th term contains the same powers of a and b.