In the arrangement shown, the magnitude of each resistance is 2 Ω. The equivalent resistance between O and A is given by (14/x) Ω. Here x is

Question

In the arrangement shown, the magnitude of each resistance is 2 Ω. The equivalent resistance between O and A is given by (14/x) Ω. Here x is (A) 22 (B) 13 (C) 15 (D) 27

Tardigrade Admin · Accepted Answer

By folding symmetry about AOC <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/b4cb63cae2b7f70efccac613347fcfb1-.png" /> R40=(14/15) Ω

Q. In the arrangement shown, the magnitude of each resistance is $2 Ω$ . The equivalent resistance between $O$ and $A$ is given by $\frac{14}{x} Ω$ . Here $x$ is

22

13

15

27

By folding symmetry about AOC

$R_{40} = \frac{14}{15} Ω$

Q. In the arrangement shown, the magnitude of each resistance is 2Ω. The equivalent resistance between O and A is given by x14​Ω. Here x is

22

13

15

27

By folding symmetry about AOC R40​=1514​Ω

Q. In the arrangement shown, the magnitude of each resistance is $2 Ω$ . The equivalent resistance between $O$ and $A$ is given by $\frac{14}{x} Ω$ . Here $x$ is

By folding symmetry about AOC

$R_{40} = \frac{14}{15} Ω$