Thank you for reporting, we will resolve it shortly
Q.
In the arrangement shown, the magnitude of each resistance is $2 \,\Omega$. The equivalent resistance between $O$ and $A$ is given by $\frac{14}{x} \Omega$. Here $x$ is
Solution:
By folding symmetry about AOC
$R_{40}=\frac{14}{15} \Omega$