In the arrangement shown in figure, m1=1 kg , m2=2 kg. Pulleys are massless and strings are light. For what value of M (in kg ) the mass m1 moves with constant velocity? (Neglect friction)

Question

In the arrangement shown in figure, m1=1 kg , m2=2 kg. Pulleys are massless and strings are light. For what value of M (in kg ) the mass m1 moves with constant velocity? (Neglect friction) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/40a6f13e7222d849618835e0807fc868-.png" /> m1=1 kg m2=2 kg am1=(g/3) m1 will move with constant velocity if a=0. So, downward acceleration should be (g/3). ⇒ T=(4 g/3) ∴ M (g/3)=(8 g/3) ⇒ M=8 kg

Q. In the arrangement shown in figure, $m_{1} = 1 k g, m_{2} = 2 k g$ . Pulleys are massless and strings are light. For what value of $M$ (in $k g$ ) the mass $m_{1}$ moves with constant velocity? (Neglect friction)

$m_{1} = 1 k g$
$m_{2} = 2 k g$
$a_{m_{1}} = \frac{g}{3}$
$m_{1}$ will move with constant velocity if $a = 0$ .
So, downward acceleration should be $\frac{g}{3}$ .
$\Rightarrow T = \frac{4 g}{3}$
$∴ M \frac{g}{3} = \frac{8 g}{3}$
$\Rightarrow M = 8 k g$

Q. In the arrangement shown in figure, m1​=1kg,m2​=2kg. Pulleys are massless and strings are light. For what value of M (in kg ) the mass m1​ moves with constant velocity? (Neglect friction)

m1​=1kg m2​=2kg am1​​=3g​ m1​ will move with constant velocity if a=0. So, downward acceleration should be 3g​. ⇒T=34g​ ∴M3g​=38g​ ⇒M=8kg

Q. In the arrangement shown in figure, $m_{1} = 1 k g, m_{2} = 2 k g$ . Pulleys are massless and strings are light. For what value of $M$ (in $k g$ ) the mass $m_{1}$ moves with constant velocity? (Neglect friction)

$m_{1} = 1 k g$
$m_{2} = 2 k g$
$a_{m_{1}} = \frac{g}{3}$
$m_{1}$ will move with constant velocity if $a = 0$ .
So, downward acceleration should be $\frac{g}{3}$ .
$\Rightarrow T = \frac{4 g}{3}$
$∴ M \frac{g}{3} = \frac{8 g}{3}$
$\Rightarrow M = 8 k g$