In the adjoining figure the potential difference between X and Y is 60 V. The potential difference the points M and N will be

Question

In the adjoining figure the potential difference between X and Y is 60 V. The potential difference the points M and N will be (A) 10 V (B) 15 V (C) 20 V (D) 30 V

Tardigrade Admin · Accepted Answer

Capacitors in series 2 C1 × V1=C × V2 2 V1=V2 ...(i) and V1+V2+V1=60 ...(ii) Solving Eqs. (i) and (ii), we get V2=30 V

Q. In the adjoining figure the potential difference between $X$ and $Y$ is $60 V$ . The potential difference the points $M$ and $N$ will be

$10 V$

$15 V$

$20 V$

$30 V$

Capacitors in series
$2 C_{1} \times V_{1} = C \times V_{2}$
$2 V_{1} = V_{2}$ ...(i)
and $V_{1} + V_{2} + V_{1} = 60$ ...(ii)
Solving Eqs. (i) and (ii), we get
$V_{2} = 30 V$

Q. In the adjoining figure the potential difference between X and Y is 60V. The potential difference the points M and N will be

10V

15V

20V

30V