Question

In the adjoining figure, the position time graph of a particle of mass $0.1kg$ is shown. The impulse at $t=2s$ is

• A. 0.02 kg m/s
• B. 0.1 kg m/s
• C. 0.2 kg m/s
• D. 0.4 kg m/s

Answer 1

Answer: (C)

From the graph, it is clear that upto $t=2.0s$,
the body moves with a constant velocity
Slope of position-time graph $=\frac{4}{2}=2m/s$
After $t=2.0s$, position-time graph is parallel to time axis which means that body comes to rest.
$\therefore$ Change in velocity $=dv=2m/s$
Impulse $=$ Change in momentum
$=dp=mdv=0.1\times 2=0.2kg-m/s$