Question

In the adjoining figure, the impedance of the circuit will be

• A. 120 ohm
• B. 50 ohm
• C. 60 ohm
• D. 90 ohm

Answer 1

Answer: (C)

$i_L=\frac{90}{30}=3A,i_C=\frac{90}{20}=4.5A$
Net current through circuit,
$i=i_C-i_L=1.5A$
$\therefore Z=\frac{V}{i}=\frac{90}{1.5}=60\Omega$