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  4. In the adjoining figure, the impedance of the circuit will be

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Q. In the adjoining figure, the impedance of the circuit will bePhysics Question Image

Alternating Current

Solution:

$i_{L}=\frac{90}{30}=3 \,A , i_{C}=\frac{90}{20}=4.5 \,A$
Net current through circuit,
$i=i_{C}-i_{L}=1.5 A$
$\therefore Z=\frac{V}{i}=\frac{90}{1.5}=60\, \Omega$