In the above question, is the acceleration vector a constant vector and what is its magnitude?

Question

In the above question, is the acceleration vector a constant vector and what is its magnitude? (A) No and 1.8 cm / s 2 (B) Yes and 1.8 cm / s 2 (C) Yes and 2.3 cm / s 2 (D) No and 2.3 cm / s 2

Tardigrade Admin · Accepted Answer

The acceleration is directed towards the centre of circle. Since this direction changes continuously, acceleration here is not a constant vector. However, the magnitude of acceleration is constant.

a = ω^{2} \cdot R = (0.44 s^{- 1})^{2} \cdot (12 c m) = 2.3 c m s^{- 2}

Q. In the above question, is the acceleration vector a constant vector and what is its magnitude?

No and $1.8 c m / s^{2}$

Yes and $1.8 c m / s^{2}$

Yes and $2.3 c m / s^{2}$

No and $2.3 c m / s^{2}$

The acceleration is directed towards the centre of circle. Since this direction changes continuously, acceleration here is not a constant vector. However, the magnitude of acceleration is constant.
$a = ω^{2} \cdot R = (0.44 s^{- 1})^{2} \cdot (12 c m) = 2.3 c m s^{- 2}$

Q. In the above question, is the acceleration vector a constant vector and what is its magnitude?

No and 1.8cm/s2

Yes and 1.8cm/s2

Yes and 2.3cm/s2

No and 2.3cm/s2

The acceleration is directed towards the centre of circle. Since this direction changes continuously, acceleration here is not a constant vector. However, the magnitude of acceleration is constant. a=ω2⋅R=(0.44s−1)2⋅(12cm)=2.3cms−2

No and $1.8 c m / s^{2}$

Yes and $1.8 c m / s^{2}$

Yes and $2.3 c m / s^{2}$

No and $2.3 c m / s^{2}$

The acceleration is directed towards the centre of circle. Since this direction changes continuously, acceleration here is not a constant vector. However, the magnitude of acceleration is constant.
$a = ω^{2} \cdot R = (0.44 s^{- 1})^{2} \cdot (12 c m) = 2.3 c m s^{- 2}$