In TeCl4 the central atom tellurium involves

Question

In TeCl4 the central atom tellurium involves (A) sp3 hybridization (B) sp3d hybridization (C) sp3d2 hybridization (D) dsp2 hybridization

Tardigrade Admin · Accepted Answer

Hybridisation = (1/2) [Number of valence electrons of central atom + no. of monovalent atoms attached to it + negative charge if any - positive charge if any] = (1/2) [6+4+0-0] =5=sp3d [∵ Te (52)=[Kr]4d105s25p4]

Q. In $TeCl X_{4}$ the central atom tellurium involves

$s p^{3}$ hybridization

$s p^{3} d$ hybridization

$s p^{3} d^{2}$ hybridization

$d s p^{2}$ hybridization

Hybridisation $= \frac{1}{2}$ [Number of valence electrons of central atom + no. of monovalent atoms attached to it + negative charge if any - positive charge if any]
$= \frac{1}{2} [6 + 4 + 0 - 0] = 5 = s p^{3} d$
$[∵ T e (52) = [Kr] 4 d^{10} 5 s^{2} 5 p^{4}]$

Q. In TeClX4​ the central atom tellurium involves

sp3 hybridization

sp3d hybridization

sp3d2 hybridization

dsp2 hybridization