In TeCl4, the central atom tellurium involves

Question

In TeCl4, the central atom tellurium involves (A)  sp3 hybridisation (B)  sp3d hybridization (C)  dsp2 hybridisation (D)  sp3d2 hybridization

Tardigrade Admin · Accepted Answer

Number of hybrid orbitais =(1/2) (no. of eloectrons in valence shell of atom + ho, of monovalent atoms - charge no cation + charge on anion Number of hybrid orbitais =(1/2) (6+4+0+0)=5 Hence, TeCl4 shows sp3d hybridisation.

Q. In $T e C l_{4},$ the central atom tellurium involves

$s p^{3}$ hybridisation

$s p^{3} d$ hybridization

$d s p^{2}$ hybridisation

$s p^{3} d^{2}$ hybridization

Number of hybrid orbitais $= \frac{1}{2}$ (no. of eloectrons in valence shell of atom $+$ ho, of monovalent atoms $-$ charge no cation $+$ charge on anion Number of hybrid orbitais $= \frac{1}{2}$ $(6 + 4 + 0 + 0) = 5$ Hence, $T e C l_{4}$ shows $s p^{3} d$ hybridisation.

Q. In TeCl4​, the central atom tellurium involves

sp3 hybridisation

sp3d hybridization

dsp2 hybridisation

sp3d2 hybridization