Question

In $ TeC{{l}_{4}}, $ the central atom tellurium involves

• A. $ s{{p}^{3}} $ hybridisation
• B. $ s{{p}^{3}}d $ hybridization
• C. $ ds{{p}^{2}} $ hybridisation
• D. $ s{{p}^{3}}{{d}^{2}} $ hybridization

Answer 1

Answer: (B)

Number of hybrid orbitais $ =\frac{1}{2} $ (no. of eloectrons in valence shell of atom $ + $ ho, of monovalent atoms $ - $ charge no cation $ + $ charge on anion Number of hybrid orbitais $ =\frac{1}{2} $ $ (6+4+0+0)=5 $ Hence, $ TeC{{l}_{4}} $ shows $ s{{p}^{3}}d $ hybridisation.