In steel, the Young's modulus and the strain at the breaking point are 2 × 1011 N / m 2 and 0.15 respectively. The stress at the breaking point for steel is therefore

Question

In steel, the Young's modulus and the strain at the breaking point are 2 × 1011 N / m 2 and 0.15 respectively. The stress at the breaking point for steel is therefore (A) 1.33 × 1011 N / m 2 (B) 1.33 × 1012 N / m 2 (C) 7.5 × 10-13 N / m 2 (D) 3 × 1010 N / m 2

Tardigrade Admin · Accepted Answer

Breaking stress = strain × Young's modulus =0.15 × 2 × 1011 =3 × 1010 N / m 2

Q. In steel, the Young's modulus and the strain at the breaking point are $2 \times 1 0^{11} N / m^{2}$ and $0.15$ respectively. The stress at the breaking point for steel is therefore

$1.33 \times 1 0^{11} N / m^{2}$

$1.33 \times 1 0^{12} N / m^{2}$

$7.5 \times 1 0^{- 13} N / m^{2}$

$3 \times 1 0^{10} N / m^{2}$

Breaking stress = strain $\times$ Young's modulus
$= 0.15 \times 2 \times 1 0^{11}$
$= 3 \times 1 0^{10} N / m^{2}$

Q. In steel, the Young's modulus and the strain at the breaking point are 2×1011N/m2 and 0.15 respectively. The stress at the breaking point for steel is therefore

1.33×1011N/m2

1.33×1012N/m2

7.5×10−13N/m2

3×1010N/m2