In series LCR circuit R=18 Ω and impedance is 33 Ω . An RMS voltage of 220 V is applied across the circuit. The true power consumed in the AC circuit is

Question

In series LCR circuit R=18 Ω and impedance is 33 Ω . An RMS voltage of 220 V is applied across the circuit. The true power consumed in the AC circuit is (A) 220W (B) 400 W (C) 600 W (D) 800 W

Tardigrade Admin · Accepted Answer

P =er m s.ir m s.cos φ =er m s.(er m s/Z).(R/Z) =(220 × 220 × 18/33 × 33) =(20 × 20 × 18/3 × 3) =20× 20× 2 =800 W

Q. In series LCR circuit $R = 18 Ω$ and impedance is $33 Ω$ . An RMS voltage of $220 V$ is applied across the circuit. The true power consumed in the AC circuit is

$220 W$

$400 W$

$600 W$

$800 W$

$P = e_{r m s} . i_{r m s} . cos ϕ$
$= e_{r m s} . \frac{e _{r m s}}{Z} . \frac{R}{Z}$
$= \frac{220 \times 220 \times 18}{33 \times 33}$
$= \frac{20 \times 20 \times 18}{3 \times 3}$
$= 20 \times 20 \times 2$
$= 800 W$

Q. In series LCR circuit R=18Ω and impedance is 33Ω . An RMS voltage of 220V is applied across the circuit. The true power consumed in the AC circuit is

220W

400W

600W

800W