In Rutherford's model, if Fe indicates electrostatic force between electron and nucleus and Fc indicates the centripetal force on revolving electron, then

Question

In Rutherford's model, if Fe indicates electrostatic force between electron and nucleus and Fc indicates the centripetal force on revolving electron, then (A) Fe=Fc (B) Fe > Fc (C) Fe < Fc (D) None of these

Tardigrade Admin · Accepted Answer

The electrostatic force of attraction, Fe between the revolving electrons and the nucleus provides the requisite centripetal force (Fc) to keep them in their orbits. Thus, for a dynamically stable orbit in a hydrogen atom Fe=Fc.

Q. In Rutherford's model, if $F_{e}$ indicates electrostatic force between electron and nucleus and $F_{c}$ indicates the centripetal force on revolving electron, then

$F_{e} = F_{c}$

$F_{e} > F_{c}$

$F_{e} < F_{c}$

None of these

The electrostatic force of attraction, $F_{e}$ between the revolving electrons and the nucleus provides the requisite centripetal force $(F_{c})$ to keep them in their orbits. Thus, for a dynamically stable orbit in a hydrogen atom $F_{e} = F_{c}$ .

Q. In Rutherford's model, if Fe​ indicates electrostatic force between electron and nucleus and Fc​ indicates the centripetal force on revolving electron, then

Fe​=Fc​

Fe​>Fc​

Fe​<Fc​