In Ψ321 the sum of angular momentum, spherical nodes and angular node is :-

Question

In Ψ321 the sum of angular momentum, spherical nodes and angular node is :- (A) (√6 h + 4 π /2 π ) (B) (√6 h/2 π )+3 (C) (√6 h + 2 π /2 π ) (D) (√6 h + 8 π /2 π )

Tardigrade Admin · Accepted Answer

ψ321⇒ n=3,ℓ =2,m=1 angular momentum =(h/2 π )√ℓ (. ℓ + 1 .)=(√6 h/2 π ) spherical node =n-ℓ -1 =3-2-1=0 Angular node =ℓ =2 sum ⇒ (√6 h/2 π )+0+2 ⇒ (√6 h + 4 π /2 π )

Q. In $Ψ_{321}$ the sum of angular momentum, spherical nodes and angular node is :-

$\frac{6 h + 4 π}{2 π}$

$\frac{6 h}{2 π} + 3$

$\frac{6 h + 2 π}{2 π}$

$\frac{6 h + 8 π}{2 π}$

$ψ_{321} \Rightarrow n = 3, ℓ = 2, m = 1$
angular momentum $= \frac{h}{2 π} ℓ (ℓ + 1) = \frac{6 h}{2 π}$
spherical node $= n - ℓ - 1$
$= 3 - 2 - 1 = 0$
Angular node $= ℓ = 2$
sum $\Rightarrow \frac{6 h}{2 π} + 0 + 2$
$\Rightarrow \frac{6 h + 4 π}{2 π}$

Q. In Ψ321​ the sum of angular momentum, spherical nodes and angular node is :-

2π6​h+4π​

2π6​h​+3

2π6​h+2π​

2π6​h+8π​