In producing chlorine through electrolysis, 100 kW power at 125 V is being consumed. The mass of chlorine per minute liberated, will be (z=0.367 × 10-6 kg / C )

Question

In producing chlorine through electrolysis, 100 kW power at 125 V is being consumed. The mass of chlorine per minute liberated, will be (z=0.367 × 10-6 kg / C ) (A) 17.61 × 10-3 kg (B) 10.61 × 10-3 kg (C) 12.61 × 10-3 kg (D) None of the above

Tardigrade Admin · Accepted Answer

From Faraday's law of electromagnetic induction, mass of electrons released is

m = Z I t

where

I

is current,

t

is time and

z

electrochemical equivalent.
Also,

P = V I

∴ I = \frac{P}{V} = \frac{100 \times 1 0 ^{3}}{125} = 800 A

m = Z I t

= 0.367 \times 1 0^{- 6} \times 800 \times 60

= 17.61 \times 1 0^{- 3} k g

Q. In producing chlorine through electrolysis, $100 kW$ power at $125 V$ is being consumed. The mass of chlorine per minute liberated, will be $(z = 0.367 \times 1 0^{- 6} k g / C)$

$17.61 \times 1 0^{- 3} k g$

$10.61 \times 1 0^{- 3} k g$

$12.61 \times 1 0^{- 3} k g$

None of the above

Q. In producing chlorine through electrolysis, 100kW power at 125V is being consumed. The mass of chlorine per minute liberated, will be (z=0.367×10−6kg/C)

17.61×10−3kg

10.61×10−3kg

12.61×10−3kg

None of the above

From Faraday's law of electromagnetic induction, mass of electrons released is m=ZIt where I is current, t is time and z electrochemical equivalent. Also, P=VI ∴I=VP​=125100×103​=800A m=ZIt =0.367×10−6×800×60 =17.61×10−3kg

Q. In producing chlorine through electrolysis, $100 kW$ power at $125 V$ is being consumed. The mass of chlorine per minute liberated, will be $(z = 0.367 \times 1 0^{- 6} k g / C)$

$17.61 \times 1 0^{- 3} k g$

$10.61 \times 1 0^{- 3} k g$

$12.61 \times 1 0^{- 3} k g$