In photoelectric effect the slope of straight line graph between stopping potential (v0) and frequency of incident light (v) gives

Question

In photoelectric effect the slope of straight line graph between stopping potential (v0) and frequency of incident light (v) gives <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-mxlspzylqzu5w2hb.jpg" /> (A) charge on electrons (B) work function of emitter (C) planck's constant (D) ratio of Planck's constant to charge on electron

Tardigrade Admin · Accepted Answer

We know that E=φ+kE ⇒ h upsilon=W+eV0 ⇒ eV0=h upsilon-W V0=((h/e)) upsilon+(- (W/e)) Compare this with equation of line y=mx+c m= slope of graph =(h/e)

Q. In photoelectric effect the slope of straight line graph between stopping potential $(v_{0})$ and frequency of incident light $(v)$ gives

charge on electrons

work function of emitter

planck's constant

ratio of Planck's constant to charge on electron

We know that
$E = ϕ + k E$
$\Rightarrow h υ = W + e V_{0}$
$\Rightarrow e V_{0} = h υ - W$
$V_{0} = (\frac{h}{e}) υ + (- \frac{W}{e})$
Compare this with equation of line $y = m x + c$
$m =$ slope of graph $= \frac{h}{e}$

Q. In photoelectric effect the slope of straight line graph between stopping potential (v0​) and frequency of incident light (v) gives