In photoelectric effect, stopping potential for a light of frequency n1 is V1. If light is replaced by another having a frequency n 2 then its stopping potential will be

Question

In photoelectric effect, stopping potential for a light of frequency n1 is V1. If light is replaced by another having a frequency n 2 then its stopping potential will be (A) V 1-( h / e )( n 2- n 1) (B) V 1+( h / e )( n 2+ n 1) (C) V 1+( h / e )( n 2-2 n 1) (D) V 1+( h / e )( n 2- n 1)

Tardigrade Admin · Accepted Answer

W 0= h v 1- e V 1 = h v 2- eV 2 e V2=h(v2-v1)+e V1 V 2=( h ( n 2- n 1)/ e )+ V 1

Q. In photoelectric effect, stopping potential for a light of frequency $n_{1}$ is $V_{1}$ . If light is replaced by another having a frequency $n_{2}$ then its stopping potential will be

$V_{1} - \frac{h}{e} (n_{2} - n_{1})$

$V_{1} + \frac{h}{e} (n_{2} + n_{1})$

$V_{1} + \frac{h}{e} (n_{2} - 2 n_{1})$

$V_{1} + \frac{h}{e} (n_{2} - n_{1})$

$W_{0} = h v_{1} - e V_{1}$
$= h v_{2} - e V_{2}$
$e V_{2} = h (v_{2} - v_{1}) + e V_{1}$
$V_{2} = \frac{h ( n _{2} - n _{1} )}{e} + V_{1}$

Q. In photoelectric effect, stopping potential for a light of frequency n1​ is V1​. If light is replaced by another having a frequency n2​ then its stopping potential will be

V1​−eh​(n2​−n1​)

V1​+eh​(n2​+n1​)

V1​+eh​(n2​−2n1​)

V1​+eh​(n2​−n1​)