In order to raise a mass of 100 kg a man of mass, 60 kg fastens a rope to it and passes the rope over a smooth pulley. He climbs the rope with an acceleration (5 g/4) relative to the rope. The tension in the rope is near to (take g=10 m s- 2 )

Question

In order to raise a mass of 100 kg a man of mass, 60 kg fastens a rope to it and passes the rope over a smooth pulley. He climbs the rope with an acceleration (5 g/4) relative to the rope. The tension in the rope is near to (take g=10 m s- 2 ) (A) 1432N (B) 928N (C) 1218N (D) 642N

Tardigrade Admin · Accepted Answer

assume block of mass 100kg is moving upward with acceleration a with respect to ground and tension in the rope is T . Then, for man T-60g=60((5 g/4) - a) ....... (.1.) ( ∵ man is climbing on the rope with acceleration (5 g/4) ) for block T-100g=100a ...... (.2.) solving equation (.1.) and (.2.) T=1218.7N≈ 1218N

Q. In order to raise a mass of $100 k g$ a man of mass, $60 k g$ fastens a rope to it and passes the rope over a smooth pulley. He climbs the rope with an acceleration $\frac{5 g}{4}$ relative to the rope. The tension in the rope is near to (take $g = 10 m s^{- 2}$ )

$1432 N$

$928 N$

$1218 N$

$642 N$

Q. In order to raise a mass of 100kg a man of mass, 60kg fastens a rope to it and passes the rope over a smooth pulley. He climbs the rope with an acceleration 45g​ relative to the rope. The tension in the rope is near to (take g=10ms−2 )

1432N

928N

1218N

642N

Q. In order to raise a mass of $100 k g$ a man of mass, $60 k g$ fastens a rope to it and passes the rope over a smooth pulley. He climbs the rope with an acceleration $\frac{5 g}{4}$ relative to the rope. The tension in the rope is near to (take $g = 10 m s^{- 2}$ )

$1432 N$

$928 N$

$1218 N$

$642 N$