In one molal solution that contains 0.5 mole of a solute, there is

Question

In one molal solution that contains 0.5 mole of a solute, there is (A) 1000 g of solvent (B) 500 mL of solvent (C) 500 g of solvent (D) 100 mL of solvent

Tardigrade Admin · Accepted Answer

m =( text Moles of solute / text Weight of solvent ( g )) × 1000 1=(0.5/ text Weight of solvent ( g )) × 1000 Weight of solvent ( g )=500 g

Q. In one molal solution that contains $0.5$ mole of a solute, there is

$1000 g$ of solvent

$500 m L$ of solvent

$500 g$ of solvent

$100 m L$ of solvent

$m = \frac{Moles of solute}{Weight of solvent ( g )} \times 1000$
$1 = \frac{0.5}{Weight of solvent ( g )} \times 1000$
Weight of solvent $(g) = 500 g$

Q. In one molal solution that contains 0.5 mole of a solute, there is

1000g of solvent

500mL of solvent

500g of solvent

100mL of solvent