In one dimensional motion, instantaneous speed v satisfies 0 le v

Question

In one dimensional motion, instantaneous speed v satisfies 0 le v < v0 . (A) The displacement in time T must always take non-negative values (B) The displacement x in time T satisfies - v0T < x < v0T  (C) The acceleration is always a non-negative number (D) The motion has no turning points

Tardigrade Admin · Accepted Answer

The maximum distance covered in time T=v0T . Therefore, for the object having one dimensional motion, the displacement x in time T satisfies - v0T < x < v0T .

Q. In one dimensional motion, instantaneous speed $v$ satisfies $0 \leq v < v_{0}$ .

The displacement in time $T$ must always take non-negative values

The displacement $x$ in time $T$ satisfies $- v_{0} T < x < v_{0} T$

The acceleration is always a non-negative number

The motion has no turning points

The maximum distance covered in time $T = v_{0} T$ . Therefore, for the object having one dimensional motion, the displacement $x$ in time $T$ satisfies $- v_{0} T < x < v_{0} T$ .

Q. In one dimensional motion, instantaneous speed v satisfies 0≤v<v0​ .

The displacement in time T must always take non-negative values

The displacement x in time T satisfies −v0​T<x<v0​T